Base | Representation |
---|---|
bin | 10110111111001100101110… |
… | …001111100011110000110111 |
3 | 111020222001210121002201102222 |
4 | 112333030232033203300313 |
5 | 101222410310304324002 |
6 | 555004412012152555 |
7 | 30203143343360222 |
oct | 2677145617436067 |
9 | 436861717081388 |
10 | 101100011011127 |
11 | 2a2393015a8a77 |
12 | b409a3916875b |
13 | 44548c82a807b |
14 | 1ad73a39445b9 |
15 | ba4c9b1e81a2 |
hex | 5bf32e3e3c37 |
101100011011127 has 2 divisors, whose sum is σ = 101100011011128. Its totient is φ = 101100011011126.
The previous prime is 101100011011099. The next prime is 101100011011193. The reversal of 101100011011127 is 721110110001101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101100011011127 - 212 = 101100011007031 is a prime.
It is a super-4 number, since 4×1011000110111274 (a number of 57 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101100011071127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550005505563 + 50550005505564.
It is an arithmetic number, because the mean of its divisors is an integer number (50550005505564).
Almost surely, 2101100011011127 is an apocalyptic number.
101100011011127 is a deficient number, since it is larger than the sum of its proper divisors (1).
101100011011127 is an equidigital number, since it uses as much as digits as its factorization.
101100011011127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14, while the sum is 17.
Adding to 101100011011127 its reverse (721110110001101), we get a palindrome (822210121012228).
The spelling of 101100011011127 in words is "one hundred one trillion, one hundred billion, eleven million, eleven thousand, one hundred twenty-seven".
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