10110002021113 has 2 divisors, whose sum is σ = 10110002021114. Its totient is φ = 10110002021112.

The previous prime is 10110002021101. The next prime is 10110002021117. The reversal of 10110002021113 is 31112020001101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9984411875344 + 125590145769 = 3159812^2 + 354387^2 .

It is a cyclic number.

It is not a de Polignac number, because 10110002021113 - 2²⁵ = 10109968466681 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10110002021093 and 10110002021102.

It is not a weakly prime, because it can be changed into another prime (10110002021117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055001010556 + 5055001010557.

It is an arithmetic number, because the mean of its divisors is an integer number (5055001010557).

Almost surely, 2^{10110002021113} is an apocalyptic number.

It is an amenable number.

10110002021113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110002021113 is an equidigital number, since it uses as much as digits as its factorization.

10110002021113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 10110002021113 its reverse (31112020001101), we get a palindrome (41222022022214).

The spelling of 10110002021113 in words is "ten trillion, one hundred ten billion, two million, twenty-one thousand, one hundred thirteen".