10110010011113 has 2 divisors, whose sum is σ = 10110010011114. Its totient is φ = 10110010011112.

The previous prime is 10110010011089. The next prime is 10110010011137. The reversal of 10110010011113 is 31111001001101.

It is a balanced prime because it is at equal distance from previous prime (10110010011089) and next prime (10110010011137).

It can be written as a sum of positive squares in only one way, i.e., 9931240023769 + 178769987344 = 3151387^2 + 422812^2 .

It is a cyclic number.

It is not a de Polignac number, because 10110010011113 - 2¹⁶ = 10110009945577 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10110010011094 and 10110010011103.

It is not a weakly prime, because it can be changed into another prime (10110010011173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055005005556 + 5055005005557.

It is an arithmetic number, because the mean of its divisors is an integer number (5055005005557).

Almost surely, 2^{10110010011113} is an apocalyptic number.

It is an amenable number.

10110010011113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110010011113 is an equidigital number, since it uses as much as digits as its factorization.

10110010011113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 10110010011113 its reverse (31111001001101), we get a palindrome (41221011012214).

The spelling of 10110010011113 in words is "ten trillion, one hundred ten billion, ten million, eleven thousand, one hundred thirteen".