Base | Representation |
---|---|
bin | 11101011011001000101… |
… | …10110010100000011111 |
3 | 10120122120101202122110112 |
4 | 32231210112302200133 |
5 | 113031012224311312 |
6 | 2052240352200235 |
7 | 133020355540046 |
oct | 16554426624037 |
9 | 3518511678415 |
10 | 1011001010207 |
11 | 35a843793771 |
12 | 143b3223907b |
13 | 7444c487c36 |
14 | 36d0b4db55d |
15 | 1b472454d22 |
hex | eb645b281f |
1011001010207 has 2 divisors, whose sum is σ = 1011001010208. Its totient is φ = 1011001010206.
The previous prime is 1011001010197. The next prime is 1011001010251. The reversal of 1011001010207 is 7020101001101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1011001010207 - 28 = 1011001009951 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1011001010191 and 1011001010200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1011001010707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505500505103 + 505500505104.
It is an arithmetic number, because the mean of its divisors is an integer number (505500505104).
Almost surely, 21011001010207 is an apocalyptic number.
1011001010207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011001010207 is an equidigital number, since it uses as much as digits as its factorization.
1011001010207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14, while the sum is 14.
Adding to 1011001010207 its reverse (7020101001101), we get a palindrome (8031102011308).
The spelling of 1011001010207 in words is "one trillion, eleven billion, one million, ten thousand, two hundred seven".
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