Base | Representation |
---|---|
bin | 1001001100011110101110… |
… | …0111010110111111010111 |
3 | 1022210111201001100122111102 |
4 | 2103013223213112333113 |
5 | 2311120300304323111 |
6 | 33300250330500315 |
7 | 2062265332455011 |
oct | 223075347267727 |
9 | 38714631318442 |
10 | 10110011011031 |
11 | 32486a4714958 |
12 | 117347a29469b |
13 | 5844a6a0c219 |
14 | 26d48197b1b1 |
15 | 127eb7eb313b |
hex | 931eb9d6fd7 |
10110011011031 has 2 divisors, whose sum is σ = 10110011011032. Its totient is φ = 10110011011030.
The previous prime is 10110011010989. The next prime is 10110011011103. The reversal of 10110011011031 is 13011011001101.
Together with next prime (10110011011103) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10110011011031 is a prime.
It is a super-2 number, since 2×101100110110312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10110011011231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055005505515 + 5055005505516.
It is an arithmetic number, because the mean of its divisors is an integer number (5055005505516).
Almost surely, 210110011011031 is an apocalyptic number.
10110011011031 is a deficient number, since it is larger than the sum of its proper divisors (1).
10110011011031 is an equidigital number, since it uses as much as digits as its factorization.
10110011011031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 11.
Adding to 10110011011031 its reverse (13011011001101), we get a palindrome (23121022012132).
The spelling of 10110011011031 in words is "ten trillion, one hundred ten billion, eleven million, eleven thousand, thirty-one".
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