10110020123213 has 2 divisors, whose sum is σ = 10110020123214. Its totient is φ = 10110020123212.

The previous prime is 10110020123171. The next prime is 10110020123237. The reversal of 10110020123213 is 31232102001101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8545174243369 + 1564845879844 = 2923213^2 + 1250938^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10110020123213 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10110020123191 and 10110020123200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10110020123243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055010061606 + 5055010061607.

It is an arithmetic number, because the mean of its divisors is an integer number (5055010061607).

Almost surely, 2^{10110020123213} is an apocalyptic number.

It is an amenable number.

10110020123213 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110020123213 is an equidigital number, since it uses as much as digits as its factorization.

10110020123213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10110020123213 its reverse (31232102001101), we get a palindrome (41342122124314).

The spelling of 10110020123213 in words is "ten trillion, one hundred ten billion, twenty million, one hundred twenty-three thousand, two hundred thirteen".