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101100212173 is a prime number
BaseRepresentation
bin101111000101000001…
…0101100111111001101
3100122221211212220121201
41132022002230333031
53124023123242143
6114240024225501
710206233424112
oct1361202547715
9318854786551
10101100212173
1139970485864
121771630b291
1396c2735b6c
144c71216909
15296ab1364d
hex178a0acfcd

101100212173 has 2 divisors, whose sum is σ = 101100212174. Its totient is φ = 101100212172.

The previous prime is 101100212093. The next prime is 101100212189. The reversal of 101100212173 is 371212001101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95260501449 + 5839710724 = 308643^2 + 76418^2 .

It is a cyclic number.

It is not a de Polignac number, because 101100212173 - 217 = 101100081101 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 101100212173.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101100212273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550106086 + 50550106087.

It is an arithmetic number, because the mean of its divisors is an integer number (50550106087).

Almost surely, 2101100212173 is an apocalyptic number.

It is an amenable number.

101100212173 is a deficient number, since it is larger than the sum of its proper divisors (1).

101100212173 is an equidigital number, since it uses as much as digits as its factorization.

101100212173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 19.

Adding to 101100212173 its reverse (371212001101), we get a palindrome (472312213274).

The spelling of 101100212173 in words is "one hundred one billion, one hundred million, two hundred twelve thousand, one hundred seventy-three".