Base | Representation |
---|---|
bin | 101111000101000001… |
… | …0101111011010110011 |
3 | 100122221211220102021112 |
4 | 1132022002233122303 |
5 | 3124023124102011 |
6 | 114240024343535 |
7 | 10206233465126 |
oct | 1361202573263 |
9 | 318854812245 |
10 | 101100222131 |
11 | 39970492297 |
12 | 17716314bab |
13 | 96c273a55c |
14 | 4c7121a3bd |
15 | 296ab1658b |
hex | 178a0af6b3 |
101100222131 has 2 divisors, whose sum is σ = 101100222132. Its totient is φ = 101100222130.
The previous prime is 101100222071. The next prime is 101100222173. The reversal of 101100222131 is 131222001101.
It is a strong prime.
It is an emirp because it is prime and its reverse (131222001101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101100222131 - 226 = 101033113267 is a prime.
It is a super-2 number, since 2×1011002221312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (101100224131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550111065 + 50550111066.
It is an arithmetic number, because the mean of its divisors is an integer number (50550111066).
Almost surely, 2101100222131 is an apocalyptic number.
101100222131 is a deficient number, since it is larger than the sum of its proper divisors (1).
101100222131 is an equidigital number, since it uses as much as digits as its factorization.
101100222131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 101100222131 its reverse (131222001101), we get a palindrome (232322223232).
The spelling of 101100222131 in words is "one hundred one billion, one hundred million, two hundred twenty-two thousand, one hundred thirty-one".
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