Base | Representation |
---|---|
bin | 10010110101001101… |
… | …01011011000100111 |
3 | 222002120210101120222 |
4 | 21122212223120213 |
5 | 131201131220312 |
6 | 4351112514555 |
7 | 505351531214 |
oct | 113246533047 |
9 | 28076711528 |
10 | 10110023207 |
11 | 4318932089 |
12 | 1b619aba5b |
13 | c5173026b |
14 | 6bca02b0b |
15 | 3e2892672 |
hex | 25a9ab627 |
10110023207 has 2 divisors, whose sum is σ = 10110023208. Its totient is φ = 10110023206.
The previous prime is 10110023197. The next prime is 10110023243. The reversal of 10110023207 is 70232001101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10110023207 - 24 = 10110023191 is a prime.
It is a super-3 number, since 3×101100232073 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10110023257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055011603 + 5055011604.
It is an arithmetic number, because the mean of its divisors is an integer number (5055011604).
Almost surely, 210110023207 is an apocalyptic number.
10110023207 is a deficient number, since it is larger than the sum of its proper divisors (1).
10110023207 is an equidigital number, since it uses as much as digits as its factorization.
10110023207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 17.
Adding to 10110023207 its reverse (70232001101), we get a palindrome (80342024308).
The spelling of 10110023207 in words is "ten billion, one hundred ten million, twenty-three thousand, two hundred seven".
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