Base | Representation |
---|---|
bin | 101111000101000001… |
… | …1000101001100011001 |
3 | 100122221212001221121212 |
4 | 1132022003011030121 |
5 | 3124023134430241 |
6 | 114240030312505 |
7 | 10206234316142 |
oct | 1361203051431 |
9 | 318855057555 |
10 | 101100311321 |
11 | 399705432a9 |
12 | 17716358735 |
13 | 96c276c029 |
14 | 4c71240ac9 |
15 | 296ab32beb |
hex | 178a0c5319 |
101100311321 has 2 divisors, whose sum is σ = 101100311322. Its totient is φ = 101100311320.
The previous prime is 101100311309. The next prime is 101100311327. The reversal of 101100311321 is 123113001101.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 92166280921 + 8934030400 = 303589^2 + 94520^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101100311321 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 101100311296 and 101100311305.
It is not a weakly prime, because it can be changed into another prime (101100311327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550155660 + 50550155661.
It is an arithmetic number, because the mean of its divisors is an integer number (50550155661).
Almost surely, 2101100311321 is an apocalyptic number.
It is an amenable number.
101100311321 is a deficient number, since it is larger than the sum of its proper divisors (1).
101100311321 is an equidigital number, since it uses as much as digits as its factorization.
101100311321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 101100311321 its reverse (123113001101), we get a palindrome (224213312422).
The spelling of 101100311321 in words is "one hundred one billion, one hundred million, three hundred eleven thousand, three hundred twenty-one".
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