Base | Representation |
---|---|
bin | 101111000101000010… |
… | …0000000111100111101 |
3 | 100122221212112101101111 |
4 | 1132022010000330331 |
5 | 3124023220243333 |
6 | 114240035442021 |
7 | 10206236355565 |
oct | 1361204007475 |
9 | 318855471344 |
10 | 101100556093 |
11 | 399706a0199 |
12 | 17716456311 |
13 | 96c2826574 |
14 | 4c712a5da5 |
15 | 296ab804cd |
hex | 178a100f3d |
101100556093 has 2 divisors, whose sum is σ = 101100556094. Its totient is φ = 101100556092.
The previous prime is 101100555971. The next prime is 101100556097. The reversal of 101100556093 is 390655001101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 100988577369 + 111978724 = 317787^2 + 10582^2 .
It is a cyclic number.
It is not a de Polignac number, because 101100556093 - 217 = 101100425021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101100556097) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550278046 + 50550278047.
It is an arithmetic number, because the mean of its divisors is an integer number (50550278047).
Almost surely, 2101100556093 is an apocalyptic number.
It is an amenable number.
101100556093 is a deficient number, since it is larger than the sum of its proper divisors (1).
101100556093 is an equidigital number, since it uses as much as digits as its factorization.
101100556093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4050, while the sum is 31.
Adding to 101100556093 its reverse (390655001101), we get a palindrome (491755557194).
The spelling of 101100556093 in words is "one hundred one billion, one hundred million, five hundred fifty-six thousand, ninety-three".
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