Search a number
-
+
101100556093 is a prime number
BaseRepresentation
bin101111000101000010…
…0000000111100111101
3100122221212112101101111
41132022010000330331
53124023220243333
6114240035442021
710206236355565
oct1361204007475
9318855471344
10101100556093
11399706a0199
1217716456311
1396c2826574
144c712a5da5
15296ab804cd
hex178a100f3d

101100556093 has 2 divisors, whose sum is σ = 101100556094. Its totient is φ = 101100556092.

The previous prime is 101100555971. The next prime is 101100556097. The reversal of 101100556093 is 390655001101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100988577369 + 111978724 = 317787^2 + 10582^2 .

It is a cyclic number.

It is not a de Polignac number, because 101100556093 - 217 = 101100425021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101100556097) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550278046 + 50550278047.

It is an arithmetic number, because the mean of its divisors is an integer number (50550278047).

Almost surely, 2101100556093 is an apocalyptic number.

It is an amenable number.

101100556093 is a deficient number, since it is larger than the sum of its proper divisors (1).

101100556093 is an equidigital number, since it uses as much as digits as its factorization.

101100556093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4050, while the sum is 31.

Adding to 101100556093 its reverse (390655001101), we get a palindrome (491755557194).

The spelling of 101100556093 in words is "one hundred one billion, one hundred million, five hundred fifty-six thousand, ninety-three".