10110110099953 has 2 divisors, whose sum is σ = 10110110099954. Its totient is φ = 10110110099952.

The previous prime is 10110110099951. The next prime is 10110110100017. The reversal of 10110110099953 is 35999001101101.

10110110099953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10098457329249 + 11652770704 = 3177807^2 + 107948^2 .

It is a cyclic number.

It is not a de Polignac number, because 10110110099953 - 2¹ = 10110110099951 is a prime.

Together with 10110110099951, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (10110110099951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055055049976 + 5055055049977.

It is an arithmetic number, because the mean of its divisors is an integer number (5055055049977).

Almost surely, 2^{10110110099953} is an apocalyptic number.

It is an amenable number.

10110110099953 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110110099953 is an equidigital number, since it uses as much as digits as its factorization.

10110110099953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10935, while the sum is 40.

The spelling of 10110110099953 in words is "ten trillion, one hundred ten billion, one hundred ten million, ninety-nine thousand, nine hundred fifty-three".