Search a number
-
+
101101110000053 is a prime number
BaseRepresentation
bin10110111111001101101111…
…101111110111100110110101
3111020222011122012001010211112
4112333031233233313212311
5101222420033130000203
6555005113031244405
730203212516542452
oct2677155757674665
9436864565033745
10101101110000053
112a239815992689
12b40a0a5219705
134454a41b93787
141ad746989c829
15ba4d1292e6d8
hex5bf36fbf79b5

101101110000053 has 2 divisors, whose sum is σ = 101101110000054. Its totient is φ = 101101110000052.

The previous prime is 101101110000047. The next prime is 101101110000071. The reversal of 101101110000053 is 350000011101101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94839414533809 + 6261695466244 = 9738553^2 + 2502338^2 .

It is a cyclic number.

It is not a de Polignac number, because 101101110000053 - 28 = 101101109999797 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101101109999992 and 101101110000037.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101101110003053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550555000026 + 50550555000027.

It is an arithmetic number, because the mean of its divisors is an integer number (50550555000027).

Almost surely, 2101101110000053 is an apocalyptic number.

It is an amenable number.

101101110000053 is a deficient number, since it is larger than the sum of its proper divisors (1).

101101110000053 is an equidigital number, since it uses as much as digits as its factorization.

101101110000053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 14.

Adding to 101101110000053 its reverse (350000011101101), we get a palindrome (451101121101154).

The spelling of 101101110000053 in words is "one hundred one trillion, one hundred one billion, one hundred ten million, fifty-three", and thus it is an aban number.