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1011011100997 is a prime number
BaseRepresentation
bin11101011011001001111…
…01010010000101000101
310120122121002202022102111
432231210331102011011
5113031022320212442
62052241352341021
7133020540365212
oct16554475220505
93518532668374
101011011100997
1135a849456067
12143b356a4771
13744515abc11
1436d0c9a6b09
151b473299b17
hexeb64f52145

1011011100997 has 2 divisors, whose sum is σ = 1011011100998. Its totient is φ = 1011011100996.

The previous prime is 1011011100959. The next prime is 1011011101043. The reversal of 1011011100997 is 7990011101101.

1011011100997 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 836555353956 + 174455747041 = 914634^2 + 417679^2 .

It is an emirp because it is prime and its reverse (7990011101101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1011011100997 - 223 = 1011002712389 is a prime.

It is a super-2 number, since 2×10110111009972 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011011100907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505505550498 + 505505550499.

It is an arithmetic number, because the mean of its divisors is an integer number (505505550499).

Almost surely, 21011011100997 is an apocalyptic number.

It is an amenable number.

1011011100997 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011011100997 is an equidigital number, since it uses as much as digits as its factorization.

1011011100997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 567, while the sum is 31.

The spelling of 1011011100997 in words is "one trillion, eleven billion, eleven million, one hundred thousand, nine hundred ninety-seven".