Base | Representation |
---|---|
bin | 10110111111001101101111… |
… | …110000010000000000100111 |
3 | 111020222011122012020012221112 |
4 | 112333031233300100000213 |
5 | 101222420033141200012 |
6 | 555005113033335235 |
7 | 30203212520440043 |
oct | 2677155760200047 |
9 | 436864565205845 |
10 | 101101110100007 |
11 | 2a239815a50796 |
12 | b40a0a526751b |
13 | 4454a41bca114 |
14 | 1ad74698c7023 |
15 | ba4d1294e122 |
hex | 5bf36fc10027 |
101101110100007 has 2 divisors, whose sum is σ = 101101110100008. Its totient is φ = 101101110100006.
The previous prime is 101101110099961. The next prime is 101101110100019. The reversal of 101101110100007 is 700001011101101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101101110100007 - 212 = 101101110095911 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 101101110099964 and 101101110100000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101101110100037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550555050003 + 50550555050004.
It is an arithmetic number, because the mean of its divisors is an integer number (50550555050004).
Almost surely, 2101101110100007 is an apocalyptic number.
101101110100007 is a deficient number, since it is larger than the sum of its proper divisors (1).
101101110100007 is an equidigital number, since it uses as much as digits as its factorization.
101101110100007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7, while the sum is 14.
Adding to 101101110100007 its reverse (700001011101101), we get a palindrome (801102121201108).
The spelling of 101101110100007 in words is "one hundred one trillion, one hundred one billion, one hundred ten million, one hundred thousand, seven".
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