Base | Representation |
---|---|

bin | 10010110101001110… |

… | …00001011000001011 |

3 | 222002120221222011102 |

4 | 21122213001120023 |

5 | 131201142111131 |

6 | 4351114452015 |

7 | 505352354645 |

oct | 113247013013 |

9 | 28076858142 |

10 | 10110113291 |

11 | 4318993833 |

12 | 1b61a3400b |

13 | c51762275 |

14 | 6bca27895 |

15 | 3e28ae1cb |

hex | 25a9c160b |

10110113291 has 2 divisors, whose sum is σ = 10110113292. Its totient is φ = 10110113290.

The previous prime is 10110113287. The next prime is 10110113303. The reversal of 10110113291 is 19231101101.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10110113291 - 2^{2} = 10110113287 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (10110113201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055056645 + 5055056646.

It is an arithmetic number, because the mean of its divisors is an integer number (5055056646).

Almost surely, 2^{10110113291} is an apocalyptic number.

10110113291 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110113291 is an equidigital number, since it uses as much as digits as its factorization.

10110113291 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 20.

Adding to 10110113291 its reverse (19231101101), we get a palindrome (29341214392).

The spelling of 10110113291 in words is "ten billion, one hundred ten million, one hundred thirteen thousand, two hundred ninety-one".

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