Base | Representation |
---|---|
bin | 1001001100011111001000… |
… | …1011000000101011101111 |
3 | 1022210111222201100200121222 |
4 | 2103013302023000223233 |
5 | 2311121011440121033 |
6 | 33300305300413555 |
7 | 2062301136515204 |
oct | 223076213005357 |
9 | 38714881320558 |
10 | 10110121020143 |
11 | 3248750822381 |
12 | 11734ab0a72bb |
13 | 5844c3748781 |
14 | 26d492415cab |
15 | 127ec2993598 |
hex | 931f22c0aef |
10110121020143 has 2 divisors, whose sum is σ = 10110121020144. Its totient is φ = 10110121020142.
The previous prime is 10110121020091. The next prime is 10110121020169. The reversal of 10110121020143 is 34102012101101.
10110121020143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10110121020143 - 26 = 10110121020079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10110121020173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055060510071 + 5055060510072.
It is an arithmetic number, because the mean of its divisors is an integer number (5055060510072).
Almost surely, 210110121020143 is an apocalyptic number.
10110121020143 is a deficient number, since it is larger than the sum of its proper divisors (1).
10110121020143 is an equidigital number, since it uses as much as digits as its factorization.
10110121020143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 10110121020143 its reverse (34102012101101), we get a palindrome (44212133121244).
The spelling of 10110121020143 in words is "ten trillion, one hundred ten billion, one hundred twenty-one million, twenty thousand, one hundred forty-three".
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