Base | Representation |
---|---|
bin | 11101011011001011000… |
… | …11001000000000011011 |
3 | 10120122121210102022101211 |
4 | 32231211203020000123 |
5 | 113031032340134321 |
6 | 2052242345123551 |
7 | 133021020613135 |
oct | 16554543100033 |
9 | 3518553368354 |
10 | 1011021021211 |
11 | 35a854011293 |
12 | 143b38a895b7 |
13 | 74453673376 |
14 | 36d1002a055 |
15 | 1b4740a90e1 |
hex | eb658c801b |
1011021021211 has 2 divisors, whose sum is σ = 1011021021212. Its totient is φ = 1011021021210.
The previous prime is 1011021021187. The next prime is 1011021021229. The reversal of 1011021021211 is 1121201201101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1011021021211 - 27 = 1011021021083 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1011021021191 and 1011021021200.
It is not a weakly prime, because it can be changed into another prime (1011021021271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505510510605 + 505510510606.
It is an arithmetic number, because the mean of its divisors is an integer number (505510510606).
Almost surely, 21011021021211 is an apocalyptic number.
1011021021211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011021021211 is an equidigital number, since it uses as much as digits as its factorization.
1011021021211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 1011021021211 its reverse (1121201201101), we get a palindrome (2132222222312).
The spelling of 1011021021211 in words is "one trillion, eleven billion, twenty-one million, twenty-one thousand, two hundred eleven".
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