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101102122012081 is a prime number
BaseRepresentation
bin10110111111001110101100…
…000100011000110110110001
3111020222021020201022200100111
4112333032230010120312301
5101222424121213341311
6555005401302221321
730203246555523031
oct2677165404306661
9436867221280314
10101102122012081
112a23a195170263
12b40a328124841
134454b73748268
141ad75240558c1
15ba4d716d4d21
hex5bf3ac118db1

101102122012081 has 2 divisors, whose sum is σ = 101102122012082. Its totient is φ = 101102122012080.

The previous prime is 101102122012069. The next prime is 101102122012091. The reversal of 101102122012081 is 180210221201101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92443321415025 + 8658800597056 = 9614745^2 + 2942584^2 .

It is a cyclic number.

It is not a de Polignac number, because 101102122012081 - 225 = 101102088457649 is a prime.

It is a super-2 number, since 2×1011021220120812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (101102122012091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50551061006040 + 50551061006041.

It is an arithmetic number, because the mean of its divisors is an integer number (50551061006041).

Almost surely, 2101102122012081 is an apocalyptic number.

It is an amenable number.

101102122012081 is a deficient number, since it is larger than the sum of its proper divisors (1).

101102122012081 is an equidigital number, since it uses as much as digits as its factorization.

101102122012081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 128, while the sum is 22.

Adding to 101102122012081 its reverse (180210221201101), we get a palindrome (281312343213182).

The spelling of 101102122012081 in words is "one hundred one trillion, one hundred two billion, one hundred twenty-two million, twelve thousand, eighty-one".