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101102122199153 is a prime number
BaseRepresentation
bin10110111111001110101100…
…000101000110100001110001
3111020222021020201200011222002
4112333032230011012201301
5101222424121240333103
6555005401310223345
730203246560232315
oct2677165405064161
9436867221604862
10101102122199153
112a23a195288869
12b40a3281b4b55
134454b737b245a
141ad75240a3b45
15ba4d71720488
hex5bf3ac146871

101102122199153 has 2 divisors, whose sum is σ = 101102122199154. Its totient is φ = 101102122199152.

The previous prime is 101102122199083. The next prime is 101102122199159. The reversal of 101102122199153 is 351991221201101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92479630256689 + 8622491942464 = 9616633^2 + 2936408^2 .

It is a cyclic number.

It is not a de Polignac number, because 101102122199153 - 212 = 101102122195057 is a prime.

It is a super-2 number, since 2×1011021221991532 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (101102122199159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50551061099576 + 50551061099577.

It is an arithmetic number, because the mean of its divisors is an integer number (50551061099577).

Almost surely, 2101102122199153 is an apocalyptic number.

It is an amenable number.

101102122199153 is a deficient number, since it is larger than the sum of its proper divisors (1).

101102122199153 is an equidigital number, since it uses as much as digits as its factorization.

101102122199153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9720, while the sum is 38.

The spelling of 101102122199153 in words is "one hundred one trillion, one hundred two billion, one hundred twenty-two million, one hundred ninety-nine thousand, one hundred fifty-three".