Base | Representation |
---|---|
bin | 10010110101001111… |
… | …00001000111101011 |
3 | 222002121012120111211 |
4 | 21122213201013223 |
5 | 131201210241212 |
6 | 4351121333551 |
7 | 505353436003 |
oct | 113247410753 |
9 | 28077176454 |
10 | 10110243307 |
11 | 4318a7248a |
12 | 1b61a972b7 |
13 | c517a94b8 |
14 | 6bca5d003 |
15 | 3e28d79a7 |
hex | 25a9e11eb |
10110243307 has 2 divisors, whose sum is σ = 10110243308. Its totient is φ = 10110243306.
The previous prime is 10110243289. The next prime is 10110243317. The reversal of 10110243307 is 70334201101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10110243307 - 219 = 10109719019 is a prime.
It is not a weakly prime, because it can be changed into another prime (10110243317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055121653 + 5055121654.
It is an arithmetic number, because the mean of its divisors is an integer number (5055121654).
Almost surely, 210110243307 is an apocalyptic number.
10110243307 is a deficient number, since it is larger than the sum of its proper divisors (1).
10110243307 is an equidigital number, since it uses as much as digits as its factorization.
10110243307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 22.
Adding to 10110243307 its reverse (70334201101), we get a palindrome (80444444408).
The spelling of 10110243307 in words is "ten billion, one hundred ten million, two hundred forty-three thousand, three hundred seven".
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