Base | Representation |
---|---|
bin | 10010110101001111… |
… | …00001000111110101 |
3 | 222002121012120112012 |
4 | 21122213201013311 |
5 | 131201210241232 |
6 | 4351121334005 |
7 | 505353436016 |
oct | 113247410765 |
9 | 28077176465 |
10 | 10110243317 |
11 | 4318a72499 |
12 | 1b61a97305 |
13 | c517a94c5 |
14 | 6bca5d00d |
15 | 3e28d79b2 |
hex | 25a9e11f5 |
10110243317 has 2 divisors, whose sum is σ = 10110243318. Its totient is φ = 10110243316.
The previous prime is 10110243307. The next prime is 10110243323. The reversal of 10110243317 is 71334201101.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6297057316 + 3813186001 = 79354^2 + 61751^2 .
It is a cyclic number.
It is not a de Polignac number, because 10110243317 - 28 = 10110243061 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10110243292 and 10110243301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10110243307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055121658 + 5055121659.
It is an arithmetic number, because the mean of its divisors is an integer number (5055121659).
Almost surely, 210110243317 is an apocalyptic number.
It is an amenable number.
10110243317 is a deficient number, since it is larger than the sum of its proper divisors (1).
10110243317 is an equidigital number, since it uses as much as digits as its factorization.
10110243317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 10110243317 its reverse (71334201101), we get a palindrome (81444444418).
The spelling of 10110243317 in words is "ten billion, one hundred ten million, two hundred forty-three thousand, three hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •