Base | Representation |
---|---|
bin | 10110111111001111100111… |
… | …000001000101000001000100 |
3 | 111020222100210122021110220120 |
4 | 112333033213001011001010 |
5 | 101222433132404001012 |
6 | 555010043351501540 |
7 | 30203313225011103 |
oct | 2677174701050104 |
9 | 436870718243816 |
10 | 101103111000132 |
11 | 2a23a65245265a |
12 | b40a5633878b0 |
13 | 4454ca05cb0a7 |
14 | 1ad75b953803a |
15 | ba4dcd43d58c |
hex | 5bf3e7045044 |
101103111000132 has 48 divisors (see below), whose sum is σ = 248420851896000. Its totient is φ = 31914772606080.
The previous prime is 101103111000121. The next prime is 101103111000139. The reversal of 101103111000132 is 231000111301101.
It is not an unprimeable number, because it can be changed into a prime (101103111000139) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 86400919 + ... + 87563262.
It is an arithmetic number, because the mean of its divisors is an integer number (5175434414500).
Almost surely, 2101103111000132 is an apocalyptic number.
101103111000132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
101103111000132 is an abundant number, since it is smaller than the sum of its proper divisors (147317740895868).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
101103111000132 is a wasteful number, since it uses less digits than its factorization.
101103111000132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 173966756 (or 173966754 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 15.
Adding to 101103111000132 its reverse (231000111301101), we get a palindrome (332103222301233).
The spelling of 101103111000132 in words is "one hundred one trillion, one hundred three billion, one hundred eleven million, one hundred thirty-two", and thus it is an aban number.
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