Base | Representation |
---|---|
bin | 11101011011001100010… |
… | …01101110110110101001 |
3 | 10120122122111110111020111 |
4 | 32231212021232312221 |
5 | 113031042433014201 |
6 | 2052243350054321 |
7 | 133021202624212 |
oct | 16554611566651 |
9 | 3518574414214 |
10 | 1011031141801 |
11 | 35a8597a400a |
12 | 143b4034a3a1 |
13 | 744557a7a95 |
14 | 36d11502409 |
15 | 1b474e07b51 |
hex | eb6626eda9 |
1011031141801 has 2 divisors, whose sum is σ = 1011031141802. Its totient is φ = 1011031141800.
The previous prime is 1011031141759. The next prime is 1011031141817. The reversal of 1011031141801 is 1081411301101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 635814864400 + 375216277401 = 797380^2 + 612549^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1011031141801 is a prime.
It is not a weakly prime, because it can be changed into another prime (1011031142801) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505515570900 + 505515570901.
It is an arithmetic number, because the mean of its divisors is an integer number (505515570901).
Almost surely, 21011031141801 is an apocalyptic number.
It is an amenable number.
1011031141801 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011031141801 is an equidigital number, since it uses as much as digits as its factorization.
1011031141801 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 22.
Adding to 1011031141801 its reverse (1081411301101), we get a palindrome (2092442442902).
The spelling of 1011031141801 in words is "one trillion, eleven billion, thirty-one million, one hundred forty-one thousand, eight hundred one".
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