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101110002121993 is a prime number
BaseRepresentation
bin10110111111010110000001…
…110000100111110100001001
3111021000000120220010201222011
4112333112001300213310021
5101223041241020400433
6555013143240255521
730203646052410304
oct2677260160476411
9437000526121864
10101110002121993
112a2425692a1497
12b40b9671715a1
13445582b1a24a7
141ad7a70831b3b
15ba51833ec3cd
hex5bf581c27d09

101110002121993 has 2 divisors, whose sum is σ = 101110002121994. Its totient is φ = 101110002121992.

The previous prime is 101110002121949. The next prime is 101110002122023. The reversal of 101110002121993 is 399121200011101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87573511557184 + 13536490564809 = 9358072^2 + 3679197^2 .

It is an emirp because it is prime and its reverse (399121200011101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101110002121993 - 225 = 101109968567561 is a prime.

It is not a weakly prime, because it can be changed into another prime (101110002122993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50555001060996 + 50555001060997.

It is an arithmetic number, because the mean of its divisors is an integer number (50555001060997).

Almost surely, 2101110002121993 is an apocalyptic number.

It is an amenable number.

101110002121993 is a deficient number, since it is larger than the sum of its proper divisors (1).

101110002121993 is an equidigital number, since it uses as much as digits as its factorization.

101110002121993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 31.

The spelling of 101110002121993 in words is "one hundred one trillion, one hundred ten billion, two million, one hundred twenty-one thousand, nine hundred ninety-three".