Base | Representation |
---|---|
bin | 1001001100100010011100… |
… | …1110011001010111000001 |
3 | 1022210121021202012102210012 |
4 | 2103020213032121113001 |
5 | 2311124322320200342 |
6 | 33300533454114305 |
7 | 2062332165206405 |
oct | 223104716312701 |
9 | 38717252172705 |
10 | 10111011100097 |
11 | 3249068199646 |
12 | 11736b91ab995 |
13 | 584605c7aabb |
14 | 26d53870d105 |
15 | 128025bb0b82 |
hex | 932273995c1 |
10111011100097 has 2 divisors, whose sum is σ = 10111011100098. Its totient is φ = 10111011100096.
The previous prime is 10111011100051. The next prime is 10111011100129. The reversal of 10111011100097 is 79000111011101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8918817900721 + 1192193199376 = 2986439^2 + 1091876^2 .
It is a cyclic number.
It is not a de Polignac number, because 10111011100097 - 228 = 10110742664641 is a prime.
It is not a weakly prime, because it can be changed into another prime (10111011100007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055505550048 + 5055505550049.
It is an arithmetic number, because the mean of its divisors is an integer number (5055505550049).
Almost surely, 210111011100097 is an apocalyptic number.
It is an amenable number.
10111011100097 is a deficient number, since it is larger than the sum of its proper divisors (1).
10111011100097 is an equidigital number, since it uses as much as digits as its factorization.
10111011100097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63, while the sum is 23.
Adding to 10111011100097 its reverse (79000111011101), we get a palindrome (89111122111198).
The spelling of 10111011100097 in words is "ten trillion, one hundred eleven billion, eleven million, one hundred thousand, ninety-seven".
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