Base | Representation |
---|---|
bin | 1001001100100010011100… |
… | …1110011001010101100111 |
3 | 1022210121021202012102122212 |
4 | 2103020213032121111213 |
5 | 2311124322320200012 |
6 | 33300533454114035 |
7 | 2062332165206216 |
oct | 223104716312547 |
9 | 38717252172585 |
10 | 10111011100007 |
11 | 3249068199574 |
12 | 11736b91ab91b |
13 | 584605c7aa4c |
14 | 26d53870d07d |
15 | 128025bb0b22 |
hex | 93227399567 |
10111011100007 has 2 divisors, whose sum is σ = 10111011100008. Its totient is φ = 10111011100006.
The previous prime is 10111011099977. The next prime is 10111011100019. The reversal of 10111011100007 is 70000111011101.
10111011100007 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10111011100007 - 28 = 10111011099751 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10111011099964 and 10111011100000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10111011100097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055505550003 + 5055505550004.
It is an arithmetic number, because the mean of its divisors is an integer number (5055505550004).
Almost surely, 210111011100007 is an apocalyptic number.
10111011100007 is a deficient number, since it is larger than the sum of its proper divisors (1).
10111011100007 is an equidigital number, since it uses as much as digits as its factorization.
10111011100007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7, while the sum is 14.
Adding to 10111011100007 its reverse (70000111011101), we get a palindrome (80111122111108).
The spelling of 10111011100007 in words is "ten trillion, one hundred eleven billion, eleven million, one hundred thousand, seven".
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