Base | Representation |
---|---|
bin | 1001001100100010011111… |
… | …0000110011110010011011 |
3 | 1022210121022101011202110201 |
4 | 2103020213300303302123 |
5 | 2311124332122334433 |
6 | 33300534415323031 |
7 | 2062332334661206 |
oct | 223104760636233 |
9 | 38717271152421 |
10 | 10111020121243 |
11 | 32490722a0338 |
12 | 1173700220477 |
13 | 584607ab8c62 |
14 | 26d5399ba93d |
15 | 128026893a7d |
hex | 93227c33c9b |
10111020121243 has 2 divisors, whose sum is σ = 10111020121244. Its totient is φ = 10111020121242.
The previous prime is 10111020121207. The next prime is 10111020121271. The reversal of 10111020121243 is 34212102011101.
10111020121243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10111020121243 - 29 = 10111020120731 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10111020121243.
It is not a weakly prime, because it can be changed into another prime (10111020121043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055510060621 + 5055510060622.
It is an arithmetic number, because the mean of its divisors is an integer number (5055510060622).
Almost surely, 210111020121243 is an apocalyptic number.
10111020121243 is a deficient number, since it is larger than the sum of its proper divisors (1).
10111020121243 is an equidigital number, since it uses as much as digits as its factorization.
10111020121243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 10111020121243 its reverse (34212102011101), we get a palindrome (44323122132344).
The spelling of 10111020121243 in words is "ten trillion, one hundred eleven billion, twenty million, one hundred twenty-one thousand, two hundred forty-three".
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