10111020131 has 2 divisors, whose sum is σ = 10111020132. Its totient is φ = 10111020130.

The previous prime is 10111020121. The next prime is 10111020151. The reversal of 10111020131 is 13102011101.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (13102011101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10111020131 - 2³⁰ = 9037278307 is a prime.

It is a super-2 number, since 2×10111020131² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10111020121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055510065 + 5055510066.

It is an arithmetic number, because the mean of its divisors is an integer number (5055510066).

Almost surely, 2^10111020131 is an apocalyptic number.

10111020131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111020131 is an equidigital number, since it uses as much as digits as its factorization.

10111020131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 10111020131 its reverse (13102011101), we get a palindrome (23213031232).

The spelling of 10111020131 in words is "ten billion, one hundred eleven million, twenty thousand, one hundred thirty-one".