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1011121021003 is a prime number
BaseRepresentation
bin11101011011010111000…
…00100110000001001011
310120122212202120211022211
432231223200212001023
5113031233440133003
62052300320325551
7133023343604542
oct16555340460113
93518782524284
101011121021003
1135a8a5502645
12143b664738b7
137446b2b6a42
1436d1d41b159
151b47cc5d96d
hexeb6b82604b

1011121021003 has 2 divisors, whose sum is σ = 1011121021004. Its totient is φ = 1011121021002.

The previous prime is 1011121020961. The next prime is 1011121021051. The reversal of 1011121021003 is 3001201211101.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1011121021003 is a prime.

It is a super-2 number, since 2×10111210210032 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1011121021403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505560510501 + 505560510502.

It is an arithmetic number, because the mean of its divisors is an integer number (505560510502).

Almost surely, 21011121021003 is an apocalyptic number.

1011121021003 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011121021003 is an equidigital number, since it uses as much as digits as its factorization.

1011121021003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1011121021003 its reverse (3001201211101), we get a palindrome (4012322232104).

The spelling of 1011121021003 in words is "one trillion, eleven billion, one hundred twenty-one million, twenty-one thousand, three".