101112120012121 has 2 divisors, whose sum is σ = 101112120012122. Its totient is φ = 101112120012120.

The previous prime is 101112120012119. The next prime is 101112120012131. The reversal of 101112120012121 is 121210021211101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 74837638265625 + 26274481746496 = 8650875^2 + 5125864^2 .

It is a cyclic number.

It is not a de Polignac number, because 101112120012121 - 2¹ = 101112120012119 is a prime.

Together with 101112120012119, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 101112120012095 and 101112120012104.

It is not a weakly prime, because it can be changed into another prime (101112120012131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556060006060 + 50556060006061.

It is an arithmetic number, because the mean of its divisors is an integer number (50556060006061).

Almost surely, 2^{101112120012121} is an apocalyptic number.

It is an amenable number.

101112120012121 is a deficient number, since it is larger than the sum of its proper divisors (1).

101112120012121 is an equidigital number, since it uses as much as digits as its factorization.

101112120012121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 16.

Adding to 101112120012121 its reverse (121210021211101), we get a palindrome (222322141223222).

The spelling of 101112120012121 in words is "one hundred one trillion, one hundred twelve billion, one hundred twenty million, twelve thousand, one hundred twenty-one".