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10111212112 = 24868172797
BaseRepresentation
bin10010110101010110…
…01101101001010000
3222002200000210110111
421122223031221100
5131201432241422
64351154211104
7505364612341
oct113253155120
928080023414
1010111212112
114319574351
121b62283a94
13c51a58461
146bcc320c8
153e2a29a77
hex25aacda50

10111212112 has 20 divisors (see below), whose sum is σ = 19592999316. Its totient is φ = 5054954240.

The previous prime is 10111212109. The next prime is 10111212113. The reversal of 10111212112 is 21121211101.

It is a happy number.

It can be written as a sum of positive squares in 2 ways, for example, as 7254950976 + 2856261136 = 85176^2 + 53444^2 .

It is a super-2 number, since 2×101112121122 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10111212092 and 10111212101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10111212113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102498 + ... + 175294.

Almost surely, 210111212112 is an apocalyptic number.

It is an amenable number.

10111212112 is a deficient number, since it is larger than the sum of its proper divisors (9481787204).

10111212112 is an equidigital number, since it uses as much as digits as its factorization.

10111212112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81486 (or 81480 counting only the distinct ones).

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 10111212112 its reverse (21121211101), we get a palindrome (31232423213).

The spelling of 10111212112 in words is "ten billion, one hundred eleven million, two hundred twelve thousand, one hundred twelve".

Divisors: 1 2 4 8 16 8681 17362 34724 69448 72797 138896 145594 291188 582376 1164752 631950757 1263901514 2527803028 5055606056 10111212112