Base | Representation |
---|---|
bin | 1001001100100011001100… |
… | …1101001110111110010011 |
3 | 1022210121210202110101222222 |
4 | 2103020303031032332103 |
5 | 2311130230300401003 |
6 | 33301005434451255 |
7 | 2062340155651166 |
oct | 223106315167623 |
9 | 38717722411888 |
10 | 10111212122003 |
11 | 324916070a353 |
12 | 1173754593b2b |
13 | 584638802285 |
14 | 26d5572b9add |
15 | 12803866cc38 |
hex | 9323334ef93 |
10111212122003 has 2 divisors, whose sum is σ = 10111212122004. Its totient is φ = 10111212122002.
The previous prime is 10111212121993. The next prime is 10111212122021. The reversal of 10111212122003 is 30022121211101.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10111212122003 - 212 = 10111212117907 is a prime.
It is a super-2 number, since 2×101112121220032 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (10111212122903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055606061001 + 5055606061002.
It is an arithmetic number, because the mean of its divisors is an integer number (5055606061002).
Almost surely, 210111212122003 is an apocalyptic number.
10111212122003 is a deficient number, since it is larger than the sum of its proper divisors (1).
10111212122003 is an equidigital number, since it uses as much as digits as its factorization.
10111212122003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 10111212122003 its reverse (30022121211101), we get a palindrome (40133333333104).
The spelling of 10111212122003 in words is "ten trillion, one hundred eleven billion, two hundred twelve million, one hundred twenty-two thousand, three".
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