Base | Representation |
---|---|
bin | 10110111111011000000000… |
… | …000111101111010001111111 |
3 | 111021000020001122021100022100 |
4 | 112333120000013233101333 |
5 | 101223110111230023403 |
6 | 555014133451120143 |
7 | 30204052434126465 |
oct | 2677300007572177 |
9 | 437006048240270 |
10 | 101112122111103 |
11 | 2a243456a42704 |
12 | b410259143053 |
13 | 4455aa846b80c |
14 | 1ad7bd2202835 |
15 | ba52595b22a3 |
hex | 5bf6001ef47f |
101112122111103 has 48 divisors (see below), whose sum is σ = 149774765160384. Its totient is φ = 65692941304320.
The previous prime is 101112122111089. The next prime is 101112122111141. The reversal of 101112122111103 is 301111221211101.
It is not a de Polignac number, because 101112122111103 - 214 = 101112122094719 is a prime.
It is a super-2 number, since 2×1011121221111032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (101112122111003) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1298051025 + ... + 1298128917.
It is an arithmetic number, because the mean of its divisors is an integer number (3120307607508).
Almost surely, 2101112122111103 is an apocalyptic number.
101112122111103 is a deficient number, since it is larger than the sum of its proper divisors (48662643049281).
101112122111103 is a wasteful number, since it uses less digits than its factorization.
101112122111103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81696 (or 81693 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 18.
Adding to 101112122111103 its reverse (301111221211101), we get a palindrome (402223343322204).
The spelling of 101112122111103 in words is "one hundred one trillion, one hundred twelve billion, one hundred twenty-two million, one hundred eleven thousand, one hundred three".
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