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1011121221199 is a prime number
BaseRepresentation
bin11101011011010111000…
…01010110111001001111
310120122212202221222221111
432231223201112321033
5113031234013034244
62052300324512451
7133023345400315
oct16555341267117
93518782858844
101011121221199
1135a8a5629aa1
12143b6654b727
137446b356bbb
1436d1d4700b5
151b47cc9ce34
hexeb6b856e4f

1011121221199 has 2 divisors, whose sum is σ = 1011121221200. Its totient is φ = 1011121221198.

The previous prime is 1011121221179. The next prime is 1011121221337. The reversal of 1011121221199 is 9911221211101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1011121221199 - 29 = 1011121220687 is a prime.

It is a super-2 number, since 2×10111212211992 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1011121221199.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011121221169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505560610599 + 505560610600.

It is an arithmetic number, because the mean of its divisors is an integer number (505560610600).

Almost surely, 21011121221199 is an apocalyptic number.

1011121221199 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011121221199 is an equidigital number, since it uses as much as digits as its factorization.

1011121221199 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 31.

The spelling of 1011121221199 in words is "one trillion, eleven billion, one hundred twenty-one million, two hundred twenty-one thousand, one hundred ninety-nine".