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10111213113207 = 321191159048859
BaseRepresentation
bin1001001100100011001101…
…0001000000111101110111
31022210121210211022202200020
42103020303101000331313
52311130231024110312
633301005512020223
72062340200250043
oct223106321007567
938717724282606
1010111213113207
113249161227028
121173754991673
13584638a8b49b
1426d557497023
151280387b678c
hex93233440f77

10111213113207 has 8 divisors (see below), whose sum is σ = 13482253764480. Its totient is φ = 6740490602040.

The previous prime is 10111213113191. The next prime is 10111213113341. The reversal of 10111213113207 is 70231131211101.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10111213113207 - 24 = 10111213113191 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10111213133207) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 79460857 + ... + 79588002.

It is an arithmetic number, because the mean of its divisors is an integer number (1685281720560).

Almost surely, 210111213113207 is an apocalyptic number.

10111213113207 is a deficient number, since it is larger than the sum of its proper divisors (3371040651273).

10111213113207 is a wasteful number, since it uses less digits than its factorization.

10111213113207 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 159070053.

The product of its (nonzero) digits is 252, while the sum is 24.

Adding to 10111213113207 its reverse (70231131211101), we get a palindrome (80342344324308).

The spelling of 10111213113207 in words is "ten trillion, one hundred eleven billion, two hundred thirteen million, one hundred thirteen thousand, two hundred seven".

Divisors: 1 3 21191 63573 159048859 477146577 3370404371069 10111213113207