10111213114231 has 2 divisors, whose sum is σ = 10111213114232. Its totient is φ = 10111213114230.

The previous prime is 10111213114183. The next prime is 10111213114243. The reversal of 10111213114231 is 13241131211101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10111213114231 - 2¹³ = 10111213106039 is a prime.

It is a super-2 number, since 2×10111213114231² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10111213124231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055606557115 + 5055606557116.

It is an arithmetic number, because the mean of its divisors is an integer number (5055606557116).

Almost surely, 2^{10111213114231} is an apocalyptic number.

10111213114231 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111213114231 is an equidigital number, since it uses as much as digits as its factorization.

10111213114231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 22.

Adding to 10111213114231 its reverse (13241131211101), we get a palindrome (23352344325332).

The spelling of 10111213114231 in words is "ten trillion, one hundred eleven billion, two hundred thirteen million, one hundred fourteen thousand, two hundred thirty-one".