101113011127 has 2 divisors, whose sum is σ = 101113011128. Its totient is φ = 101113011126.

The previous prime is 101113011053. The next prime is 101113011149. The reversal of 101113011127 is 721110311101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101113011127 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101113011427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556505563 + 50556505564.

It is an arithmetic number, because the mean of its divisors is an integer number (50556505564).

Almost surely, 2^101113011127 is an apocalyptic number.

101113011127 is a deficient number, since it is larger than the sum of its proper divisors (1).

101113011127 is an equidigital number, since it uses as much as digits as its factorization.

101113011127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 42, while the sum is 19.

Adding to 101113011127 its reverse (721110311101), we get a palindrome (822223322228).

The spelling of 101113011127 in words is "one hundred one billion, one hundred thirteen million, eleven thousand, one hundred twenty-seven".