Base | Representation |
---|---|
bin | 101111000101011001… |
… | …1100110111001111001 |
3 | 100122222202000020112201 |
4 | 1132022303212321321 |
5 | 3124034414013223 |
6 | 114241203110201 |
7 | 10206450410446 |
oct | 1361263467171 |
9 | 318882006481 |
10 | 101113032313 |
11 | 39977741817 |
12 | 1771a672361 |
13 | 96c52a4247 |
14 | 4c72bd29cd |
15 | 296bce6ead |
hex | 178ace6e79 |
101113032313 has 2 divisors, whose sum is σ = 101113032314. Its totient is φ = 101113032312.
The previous prime is 101113032277. The next prime is 101113032401. The reversal of 101113032313 is 313230311101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 78889080384 + 22223951929 = 280872^2 + 149077^2 .
It is an emirp because it is prime and its reverse (313230311101) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101113032313 is a prime.
It is not a weakly prime, because it can be changed into another prime (101113030313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556516156 + 50556516157.
It is an arithmetic number, because the mean of its divisors is an integer number (50556516157).
Almost surely, 2101113032313 is an apocalyptic number.
It is an amenable number.
101113032313 is a deficient number, since it is larger than the sum of its proper divisors (1).
101113032313 is an equidigital number, since it uses as much as digits as its factorization.
101113032313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 101113032313 its reverse (313230311101), we get a palindrome (414343343414).
The spelling of 101113032313 in words is "one hundred one billion, one hundred thirteen million, thirty-two thousand, three hundred thirteen".
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