Base | Representation |
---|---|
bin | 10010110101010111… |
… | …00101100011000111 |
3 | 222002200012202202211 |
4 | 21122223211203013 |
5 | 131201443410043 |
6 | 4351200244251 |
7 | 505365500653 |
oct | 113253454307 |
9 | 28080182684 |
10 | 10111310023 |
11 | 4319630971 |
12 | 1b62310687 |
13 | c51a90ba9 |
14 | 6bcc59a63 |
15 | 3e2a48a9d |
hex | 25aae58c7 |
10111310023 has 2 divisors, whose sum is σ = 10111310024. Its totient is φ = 10111310022.
The previous prime is 10111309927. The next prime is 10111310029. The reversal of 10111310023 is 32001311101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10111310023 - 217 = 10111178951 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10111309985 and 10111310012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10111310029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055655011 + 5055655012.
It is an arithmetic number, because the mean of its divisors is an integer number (5055655012).
Almost surely, 210111310023 is an apocalyptic number.
10111310023 is a deficient number, since it is larger than the sum of its proper divisors (1).
10111310023 is an equidigital number, since it uses as much as digits as its factorization.
10111310023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 10111310023 its reverse (32001311101), we get a palindrome (42112621124).
The spelling of 10111310023 in words is "ten billion, one hundred eleven million, three hundred ten thousand, twenty-three".
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