1011131113211 has 2 divisors, whose sum is σ = 1011131113212. Its totient is φ = 1011131113210.

The previous prime is 1011131113163. The next prime is 1011131113217. The reversal of 1011131113211 is 1123111311101.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1011131113211 - 2¹⁴ = 1011131096827 is a prime.

It is a super-2 number, since 2×1011131113211² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1011131113211.

It is not a weakly prime, because it can be changed into another prime (1011131113217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505565556605 + 505565556606.

It is an arithmetic number, because the mean of its divisors is an integer number (505565556606).

Almost surely, 2^{1011131113211} is an apocalyptic number.

1011131113211 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011131113211 is an equidigital number, since it uses as much as digits as its factorization.

1011131113211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 17.

Adding to 1011131113211 its reverse (1123111311101), we get a palindrome (2134242424312).

The spelling of 1011131113211 in words is "one trillion, eleven billion, one hundred thirty-one million, one hundred thirteen thousand, two hundred eleven".