101113112143 has 2 divisors, whose sum is σ = 101113112144. Its totient is φ = 101113112142.

The previous prime is 101113112053. The next prime is 101113112257. The reversal of 101113112143 is 341211311101.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101113112143 is a prime.

It is a super-2 number, since 2×101113112143² (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 101113112143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101113112843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556556071 + 50556556072.

It is an arithmetic number, because the mean of its divisors is an integer number (50556556072).

Almost surely, 2^101113112143 is an apocalyptic number.

101113112143 is a deficient number, since it is larger than the sum of its proper divisors (1).

101113112143 is an equidigital number, since it uses as much as digits as its factorization.

101113112143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 101113112143 its reverse (341211311101), we get a palindrome (442324423244).

The spelling of 101113112143 in words is "one hundred one billion, one hundred thirteen million, one hundred twelve thousand, one hundred forty-three".