101113113330230 has 16 divisors (see below), whose sum is σ = 184496804050464. Its totient is φ = 39891200875200.

The previous prime is 101113113330199. The next prime is 101113113330239. The reversal of 101113113330230 is 32033311311101.

It is a junction number, because it is equal to n+sod(n) for n = 101113113330196 and 101113113330205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101113113330239) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 69255556346 + ... + 69255557805.

It is an arithmetic number, because the mean of its divisors is an integer number (11531050253154).

Almost surely, 2^{101113113330230} is an apocalyptic number.

101113113330230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

101113113330230 is a deficient number, since it is larger than the sum of its proper divisors (83383690720234).

101113113330230 is a wasteful number, since it uses less digits than its factorization.

101113113330230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 138511114231.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 101113113330230 its reverse (32033311311101), we get a palindrome (133146424641331).

The spelling of 101113113330230 in words is "one hundred one trillion, one hundred thirteen billion, one hundred thirteen million, three hundred thirty thousand, two hundred thirty".