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10111312027 is a prime number
BaseRepresentation
bin10010110101010111…
…00110000010011011
3222002200012212112001
421122223212002123
5131201443441102
64351200301431
7505365506545
oct113253460233
928080185461
1010111312027
114319632423
121b62311877
13c51a91a8b
146bcc5a695
153e2a49487
hex25aae609b

10111312027 has 2 divisors, whose sum is σ = 10111312028. Its totient is φ = 10111312026.

The previous prime is 10111312021. The next prime is 10111312031. The reversal of 10111312027 is 72021311101.

10111312027 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (72021311101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10111312027 - 223 = 10102923419 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10111311995 and 10111312013.

It is not a weakly prime, because it can be changed into another prime (10111312021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055656013 + 5055656014.

It is an arithmetic number, because the mean of its divisors is an integer number (5055656014).

Almost surely, 210111312027 is an apocalyptic number.

10111312027 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111312027 is an equidigital number, since it uses as much as digits as its factorization.

10111312027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84, while the sum is 19.

Adding to 10111312027 its reverse (72021311101), we get a palindrome (82132623128).

The spelling of 10111312027 in words is "ten billion, one hundred eleven million, three hundred twelve thousand, twenty-seven".