10111312031 has 2 divisors, whose sum is σ = 10111312032. Its totient is φ = 10111312030.

The previous prime is 10111312027. The next prime is 10111312051. The reversal of 10111312031 is 13021311101.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (13021311101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10111312031 - 2² = 10111312027 is a prime.

It is a super-2 number, since 2×10111312031² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10111311997 and 10111312015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10111312021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055656015 + 5055656016.

It is an arithmetic number, because the mean of its divisors is an integer number (5055656016).

Almost surely, 2^10111312031 is an apocalyptic number.

10111312031 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111312031 is an equidigital number, since it uses as much as digits as its factorization.

10111312031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 10111312031 its reverse (13021311101), we get a palindrome (23132623132).

The spelling of 10111312031 in words is "ten billion, one hundred eleven million, three hundred twelve thousand, thirty-one".