Base | Representation |
---|---|
bin | 10010110101010111… |
… | …00110001001000010 |
3 | 222002200012220002201 |
4 | 21122223212021002 |
5 | 131201443444300 |
6 | 4351200303414 |
7 | 505365511021 |
oct | 113253461102 |
9 | 28080186081 |
10 | 10111312450 |
11 | 4319632778 |
12 | 1b62311b6a |
13 | c51a92025 |
14 | 6bcc5a8b8 |
15 | 3e2a4966a |
hex | 25aae6242 |
10111312450 has 12 divisors (see below), whose sum is σ = 18807041250. Its totient is φ = 4044524960.
The previous prime is 10111312447. The next prime is 10111312483. The reversal of 10111312450 is 5421311101.
It can be written as a sum of positive squares in 3 ways, for example, as 8048063521 + 2063248929 = 89711^2 + 45423^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 101113075 + ... + 101113174.
Almost surely, 210111312450 is an apocalyptic number.
10111312450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
10111312450 is a deficient number, since it is larger than the sum of its proper divisors (8695728800).
10111312450 is a wasteful number, since it uses less digits than its factorization.
10111312450 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 202226261 (or 202226256 counting only the distinct ones).
The product of its (nonzero) digits is 120, while the sum is 19.
Adding to 10111312450 its reverse (5421311101), we get a palindrome (15532623551).
The spelling of 10111312450 in words is "ten billion, one hundred eleven million, three hundred twelve thousand, four hundred fifty".
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