1011131300133 has 24 divisors (see below), whose sum is σ = 1495797896736. Its totient is φ = 657975520800.

The previous prime is 1011131300111. The next prime is 1011131300147. The reversal of 1011131300133 is 3310031311101.

1011131300133 is a `hidden beast` number, since 101 + 1 + 131 + 300 + 133 = 666.

It is not a de Polignac number, because 1011131300133 - 2¹² = 1011131296037 is a prime.

It is a super-2 number, since 2×1011131300133² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011131300033) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6957735 + ... + 7101572.

It is an arithmetic number, because the mean of its divisors is an integer number (62324912364).

Almost surely, 2^{1011131300133} is an apocalyptic number.

It is an amenable number.

1011131300133 is a deficient number, since it is larger than the sum of its proper divisors (484666596603).

1011131300133 is a wasteful number, since it uses less digits than its factorization.

1011131300133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14059505 (or 14059502 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 18.

Adding to 1011131300133 its reverse (3310031311101), we get a palindrome (4321162611234).

The spelling of 1011131300133 in words is "one trillion, eleven billion, one hundred thirty-one million, three hundred thousand, one hundred thirty-three".