10111313112 has 16 divisors (see below), whose sum is σ = 25278282840. Its totient is φ = 3370437696.

The previous prime is 10111313099. The next prime is 10111313119. The reversal of 10111313112 is 21131311101.

10111313112 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 10111313091 and 10111313100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10111313119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 210652333 + ... + 210652380.

Almost surely, 2^10111313112 is an apocalyptic number.

10111313112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

10111313112 is an abundant number, since it is smaller than the sum of its proper divisors (15166969728).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10111313112 is a wasteful number, since it uses less digits than its factorization.

10111313112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 421304722 (or 421304718 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 10111313112 its reverse (21131311101), we get a palindrome (31242624213).

The spelling of 10111313112 in words is "ten billion, one hundred eleven million, three hundred thirteen thousand, one hundred twelve".