10111323003113 has 2 divisors, whose sum is σ = 10111323003114. Its totient is φ = 10111323003112.

The previous prime is 10111323003091. The next prime is 10111323003163. The reversal of 10111323003113 is 31130032311101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9391791547609 + 719531455504 = 3064603^2 + 848252^2 .

It is an emirp because it is prime and its reverse (31130032311101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10111323003113 - 2¹⁰ = 10111323002089 is a prime.

It is not a weakly prime, because it can be changed into another prime (10111323003163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055661501556 + 5055661501557.

It is an arithmetic number, because the mean of its divisors is an integer number (5055661501557).

Almost surely, 2^{10111323003113} is an apocalyptic number.

It is an amenable number.

10111323003113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111323003113 is an equidigital number, since it uses as much as digits as its factorization.

10111323003113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 10111323003113 its reverse (31130032311101), we get a palindrome (41241355314214).

The spelling of 10111323003113 in words is "ten trillion, one hundred eleven billion, three hundred twenty-three million, three thousand, one hundred thirteen".