Base | Representation |
---|---|
bin | 1001001100100011100111… |
… | …0100001101100100011011 |
3 | 1022210122002111002202100121 |
4 | 2103020321310031210123 |
5 | 2311130442142100123 |
6 | 33301024435214111 |
7 | 2062343003302654 |
oct | 223107164154433 |
9 | 38718074082317 |
10 | 10111323003163 |
11 | 3249208262a78 |
12 | 1173785747337 |
13 | 584655785725 |
14 | 26d567d0052b |
15 | 12804327175d |
hex | 93239d0d91b |
10111323003163 has 2 divisors, whose sum is σ = 10111323003164. Its totient is φ = 10111323003162.
The previous prime is 10111323003113. The next prime is 10111323003167. The reversal of 10111323003163 is 36130032311101.
It is a strong prime.
It is an emirp because it is prime and its reverse (36130032311101) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10111323003163 is a prime.
It is not a weakly prime, because it can be changed into another prime (10111323003167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055661501581 + 5055661501582.
It is an arithmetic number, because the mean of its divisors is an integer number (5055661501582).
Almost surely, 210111323003163 is an apocalyptic number.
10111323003163 is a deficient number, since it is larger than the sum of its proper divisors (1).
10111323003163 is an equidigital number, since it uses as much as digits as its factorization.
10111323003163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 10111323003163 its reverse (36130032311101), we get a palindrome (46241355314264).
The spelling of 10111323003163 in words is "ten trillion, one hundred eleven billion, three hundred twenty-three million, three thousand, one hundred sixty-three".
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